Distance between North Vernon IN and Seymour IN
The distance from North Vernon to Seymour is 25 kilometers by road. Road takes approximately 18 minutes.
Shortest distance by air | 24 km ✈️ |
Car route length | 25 km 🚗 |
Driving time | 18 min |
Fuel amount | 2 L |
Fuel cost | 3.9 CAD |
Point | Distance | Time | Fuel | |
North Vernon | 0 km | 00 min | 0.0 L | |
US 50 25 km, 18 min
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Seymour | 25 km | 18 min | 1.6 L |
Hotels of Seymour
Frequently Asked Questions
How much does it cost to drive from North Vernon to Seymour?
Fuel cost: 3.9 CAD
This fuel cost is calculated as: (Route length 25 km / 100 km) * (Fuel consumption 8 L/100 km) * (Fuel price 1.92 CAD / L)
You can adjust fuel consumption and fuel price here.
How long is a car ride from North Vernon to Seymour?
Driving time: 18 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
- 14 km with a maximum speed 90 km/h = 9 min
- 6 km with a maximum speed 80 km/h = 4 min
- 3 km with a maximum speed 72 km/h = 2 min
- 1 km with a maximum speed 56 km/h = 1 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is North Vernon to Seymour by land?
The distance between North Vernon and Seymour is 25 km by road.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of North Vernon and Seymour respectively.
Where is North Vernon in relation to Seymour?
North Vernon is located 24 km east of Seymour.
North Vernon has geographic coordinates: latitude 39.00616, longitude -85.62358.
Seymour has geographic coordinates: latitude 38.95922, longitude -85.89025.
Which highway goes from North Vernon to Seymour?
The route from North Vernon to Seymour follows US 50.